Multiple Resources in Try-With-Resources

Direct Answer

Yes. Separate resources with semicolons. Initializers run left to right, and every successfully initialized resource is closed in reverse order. If a later initializer fails, earlier resources are still closed. If the body succeeds but several closes fail, the first close failure is primary and later close failures are suppressed; if the body fails, close failures are suppressed under the body failure.

Code Example

Two resources separated by a semicolon — watch the output close B before A.

static class Res implements AutoCloseable {
    final String name;
    Res(String name) { this.name = name; System.out.println("open " + name); }
    public void close() { System.out.println("close " + name); }
}

public static void main(String[] args) {
    try (Res a = new Res("A");
         Res b = new Res("B")) {     // semicolons between resources
        System.out.println("using A and B");
    }
}
// Output:
// open A
// open B
// using A and B
// close B   <- reverse order
// close A

Common Mistakes & Pitfalls

• Using commas instead of semicolons between resources — won't compile.
• Assuming declaration order = close order. It's the reverse.
• Manually closing in the wrong order in legacy code — leads to 'connection already closed' errors.
• Cramming unrelated resources into one header when separate try blocks would read clearer.